Ans) by solving we get x=2 n y=6 or x=6 n y=2Sub these values in x(1+y)+y we get 20
Ans is C
2)There are 24 oranges in 1 bag.and 8 bags in 1 box then how many dozens in 24 boxes.
Ans) 1 bag contains 2 dozens1 box contains 2*8=16 dozens24 boxes contains 24*16=384 dozens
3) a sphere with a radius of r=1 metre....it is revolving around its vertical axis and completes one rotation in 1 second.....find the speed at which it is rotating and it is in the range ofa)0 to pieb)1 to piec)0 to 2pied)1 to 2pie
Ans) think that the person is trying to ask the speed of not only the peripheral point but also each and every point on the sphere......
consider 'equator' of the sphere... the distance will be 2pi and in 1 sec, the speed will be 2pi cm/sec..
now consider the 'tropic of cancer'... or any arbitrary point on the sphere..... the distance will definitely be less than 2pi so speed will be less than 2pi cm/sec....
now consider the topmost point of the vertical axis. the distance covered by this point is 0 so the speed will be zero...
therefore tha answer is C. 0 TO 2PI....
4) there are "r" sections and each section is divide into "t" no.of fields and beth n jordan water these fields everyday equally ...if on monday beth does his share of watering and also 1/3 of jordans work.......then column a column bbeths normal share rt/4of workAns) beths normal share of work is same as jordan that is rt/2that thing abt 1/3 rd work we dont have to solve anything its just to confuse tats it.....so its A as rt/2>rt/4
5) ann deposited $10,000 for x yrs at an interest of 6%.... while david deposited $ 12,000 for y yrs at interest of 4.5%...... col A col Bamnt ann earned amnt david earnedAns) as column a : 10000(1.06)^xand column b: 12000(1.045)^y
x and y can take any value greater than 0 D
6) A CIRCLE WAS INSCRIBED IN A SQUARE.AREA OF SQUARE IS 36PIE.WHAT IS THE AREA OF CIRCLE.Ans) area of square=>a*a=36pia=6 root pi=diameter of circleradius of circle r=3 root piarea of circle=9(pi*pi)7) I DONT REMEMBER NAMES BUT LET THEM BE A,B,C.AGE OF A IS TWICE THAT OF B AND HALF OF C col a: col b:average arthimethic mean of their ages 3
ans is D (I am not sure)
8) n>1cola colB115n 215(n-1) ans) is D
9) z>y>x>1 cola colBz(x+y+1) y(x+z+1)ans) A
10) A()B=-A^2B then find 2()-1problem on symbolANS) (-2) ^2(-1)
(-2)^(-2)
1/(-2)^2=1/4
11) 1)5 < x <9 meet="{(-1+2)/2,(-2+1)/2}=(1/2,-1/2)19)" x100="=40%" 3x="4then">std. deviation of series 1col B-->std. deviation of series 2
Ans:mean of series 1=13/3S.D of series 1=(10/3)root3Mean of series 2= 26/3S.D of series 2=(20/3)root3B is the ans
20) For road widening the length of a rectangular plot is decreased by 15% and its breadth is
increased by 15%.col A-->area of the original plot col B-->area of the changed plot
Ans) A consider a rectangle of sides 100*521) k is a +ve integer. The function f(x) is defined asf(x)= remainder when x is divided by k ==> f(x) = x%k
then what is the value of k , if f(k+25)=3
Ans: then what is the value of k , if f(k+25)=3
c the function goes like k+25%k=3
now for k+25 to be exactly divisible by k u will have to subtract 3 so the function should be k+22
now k+22/k is perfectly divisible
so 1+22/k only 2 and 11 r factors of 22 so take k as 2 and 11
thus 11 is the answer as 2 does not fit
22) two cylindrical containers are there. one with internal radius 3 inches other with internal radius 6 inches. The 3 inch cylinder is of 10 inch height of which upto 9 inches was filled with a liquid. what would be the depth of the the liquid in the 2nd container if 1st container is emptied into the second container(previously empty)
Ans: 2.25 inches
23) xy>0
col a:--> ycol b:--> 0
Ans: D
24) z= [(123)^4]-[(123)^3]+[(123)^2]-(123)
if z is divided by 122 what is the remainder?
0....1....2....3....4
Ans: take 123^3 common from 1st bracket n remaining will be ({123-1}=122)... nsimilarly 123 from 2nd bracket n we get{(123*122)nnn finally take 122* 123 from d result
Ans is 0
25) A circle is inscribed in a square.col A colBdiameter of circle diagonal of square
Diameter of a circle=side of a square
Diagonal of a square>side of a square
Ans is B
26) a @ b is defined as -(a to the power -2b) so what is the value of3 @ 2
a)12 b)-81 c)1/81 d)-1/81 e)-12
ans is -1/81
27) circle and line lie on the same planeline l passes through the centre of the circlecola col bno.of points the line 2intersects with the circle
Ans is C
28)probablity question : they have given 3 bags all have red and white marbles: in first bag 4r n 6w second bag : 5r , 6w and third bag 5 red 5 w , they asked: if one marble is taken from first bag and tarsfer to second bag what is the probablity that it is red?( they gave numbers to the bag so no need of third bag it is just for confusion)
the ans is :(4c1/10c1 * 6c1/12c1)+ (6c1/10c1 * 5c1/12c1)
29)a 5-ltrs jug contains 4-ltrs of salt water solution that is 15% salt..if 1.5 ltrs of solution spills out of the jug,,n the jug is then filled to capacity wth water,,approximately what % of resulting solution in the jug is salt?a)71/2 % b)93/8 % c)101/2 % d) 12% e)15% ans 7.5%
30) parallegram opposite angles are given 7x,120another angle 3y cola col bx y ans) in parallelogram opposite sides are equalso 7x=120 => x=120/7sum of other two opposite angles=360-240=120=>3y=120 => y=60
Ans is B 31) a triangle was given one angle is 40,he asked the sum of two exterior angles at the base.ans:220
32)given z=4^x+4^x+4^x+4^x.and asked to find z^2ans): z=4*4^x=4^(x+1)z^2=4^2(x+1)=16^(x+1)
33) col a:(5+1/4)^2+(5-1/4)^2col b:50ans: cola:50+1/16+1/16colb:50ans is A
34 )given that avg of y women is (),avg of m men is 60,avg of age of both of them is 56.cola:ycolb:mans:cola
Q is wrong
35)two computer square chips r there x,y.side of y is 0.1 more than that of x and the area of y is 0.75 more than that of x.find the side of y.ans) y=x+0.1(x+0.1)^2=0.75+x^2On calculating x=3.7Y=3.7+0.1=3.8
ans:3.8 36)a rectangle was inscribed in a circle,diameter was given,side s of rectangle were x,2x.asked to find the area of rectangle.ans:32
37)one di question relating to full time and part time employees,ans:3/16
38)col a:no from 1 to 100 inclusive,which do not contain multiples of 3 but have multiples of 7.col b:10
7,14,28,35,49,56,70,77,91,98 are the multiples of 7 which are not multiples of 3Total 10ans:c39) 1)5/0.092)0.5/0.93).05/.000094)0.005/.095)5000/90wats the least of the given values...ans) 1)500/92)5/93)5000/94)5/905)5000/90
4th option is the least of all
40) Quadrilateral ABCDangle DAB=60degreesangle ABC=95 degrees
and AD is extended to E, E joined to C such that B,C , E are in a straight linesimilarly AB is extended to F , and F also joined to C such that D,C,F are in a straight linethen angle EDC=alpha degreesangle BFC = beta degreescolumn Aalphacolumn Bbeta+55 degrees
ans A,http://www.orkut.com/Album.aspx?uid=4292267246257639284for figure derive x+alph=155;x+b=95;angle bcf=x assume;then we obtain alp=beta+60=(beta+55)+5=>alph-5=beta+55,colA=alpha;col B=alpha-5
41) two numbers A and B lie in between 240 and 290tens place of A is 8,units place is xtens place of B is 6, units place is ycolumn AA-Bcolumn B20
Ans) A=28X B=26Y
Consider max of 28X n min of 26Y i.e 289 n 260 =>A-B=289-260=29Consider min of 28X n max of 26Y i.e 280 n 269 =>A-B=280-269=11
Ans is D
42) n>2: column A-----115*ncolumn B-----215(n-1)
Ans) is B
43) y=10x +7 col a tens digit of x col b units digit of y
Ans) is D data insufficient
44) 1) ratio of prob of divisibles of 3 between 1-50&51-100;
ans) 16:17
45)if 1 < x <3 3="4.4/3=1.464x-3=4.4-3=1.4" x="1.1">xcol b:--->yAns) is D data insufficient
48) a rectangle was of side 8 & 4 and qudrilateral is given and the side of quadi is the side of rectangle i.e 8 n the angle made by the quadi and tri is 45degcola col barea of the quadi 15
ans d question incomplete
49) One Biggest rectangle contng a smaller one, a a smallest rectangle inscribed in that smaler rectangle. The length and breadth of biggest one are 8x4. the length and breadth of biggest one is four times than that of the smallest one. the length and brdth of biggest one is twice than that of middle one. the region of smallest rectangle and the biggest one except the middle rect are shaded and they asked to find the area of the shaded region.ans. Area of big rect 8*4=32
Area of small rect=2*1=2
Area of middle rect=4*2=8
Area of shaded region= 32-8+2=26
50) A tabulated colums r given.classes medianscore no of studentsclassA 74 50classB 78 65cola colBmedian score of 115 stdnds 76
ans d coz median cn be anything... it depends on the data
answer for this isDcause it may happen that all the students in calss A have same marks ie 74 and all in B have 78......or maybe they have different marks cause median is just the central value when the score are arranged in increasing order..............so u can not determin the median for 115 students 51) l3x-2l = 4colA colBlxl 4Ans) x=2 n -2/3 only satisfies 3x-2=42=2<4-2/3=2/3<4 2=""> 18n+20/2n+2=>9n+10/n+1
53) barx= 1-x, then for all values of x, y=barx, then find value of barY.
Ans) Y=1-xBary=bar1-x=1-(1-x)=x
54) colA colB1/.001+1/.9999 1/.002+ 1/.998
Ans) 1000+10000/9999 > 500+10000/9980
Ans is A
55) 4*(14^10)*(7^2)
Ans) 2^2*(2^10*7^10)*7^2=>2^12*7^12=>(2*7)^12=>14^12
56)Acircle with an angle inscribed in semicercle of it. the arms of the angle other than diameter are 6 & r then find area of circle.
Ans) angle subtende by diameter is 90 so it is the hypotenuse =2r
Applyng pythogerous theoreme (2r)^2=6^2+r^2
4r^2=36+r^23r^2=36r=2root3 area of circle= pi*r(2root3)^2=12pi
57) An empty swimming pool can be filled to capacity through an inlet pipe in 3 hours, and it can be completely drained by a drainpipe in 6 hours. If both pipes are fully open at the same time, in how many hours will the empty pool be filled to capacity?A. 4B. 4.5C. 5D. 5.5E. 6
Ans) it takes 3 hrs to full the tank and 6 hrs to empty so if the both pipes are started for every 3 hrs the tank empties to half..{half tank} so to fill completely it takes another 3 hrs ...i think u got it........the ans, is 6hrs
58) the number of 7 digit arrangements of a,b,c,d,e,f,g, with d in 4th place..
Ans) 6!=720 3) a sphere with a radius of r=1 metre....it is revolving around its vertical axis and completes one rotation in 1 second.....find the speed at which it is rotating and it is in the range ofa)0 to pieb)1 to piec)0 to 2pied)1 to 2pie
the question is based on the angular velocity of rotation... which will be constant for all points. however the linear vel will differ frmo [0 to 2p ] 28)probablity question : they have given 3 bags all have red and white marbles: in first bag 4r n 6w second bag : 5r , 6w and third bag 5 red 5 w , they asked: if one marble is taken from first bag and tarsfer to second bag what is the probablity that it is red?( they gave numbers to the bag so no need of third bag it is just for confusion)
we don even need to consider about second bag either ....
taking one ball frm first bag and tht being red ..... so answer is 4c1/10c1 59) A motorcycle stunts man belonging to a fair, rides over the vertical walls of a circular well at an average speed of 54 kph for 5 minutes. If the radius of the well is 5 meters then the distance traveled is:A. 2.5 kms B. 3.5 kms C. 4.5 kms D. 5.5 kms E. None of the above ans) distance traveled=v*t=54*5/60=4.5kmsradius is given to confuse u
60) If 1 cm on a map corresponds to an actual distance of 40 kms. And the distance on the map between Bombay and Calcutta is 37.5 cms., the actual distance between them is :A. 375 kms B. 3750 kms C. 1500 kms D. 1375 kms E. None of the aboveAns) 37*40=1480km .5cm=20km(37+0.5)cm=1480+20=1500km
61) A box contains 90 nuts each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg., then the weight of the empty box is :A. 10 kg B. 10.5 kg C. 11 kg D. 11.5 kg E. None of the above Ans) 90*100=9000gm=9kg100*150=15000=15kgTotal=24kgWeigh of empty box=35.5-24=11.5
62) If the radius of a circle is increased by 20% then the area is increased by :A. 44% B. 120% C. 144% D. 40% E. None of the above Ans) let r=10 area of circle=100piRadius increased by 20% …now r=12Area of circle=144piArea increased by 44%
63) If x, y, and z are consecutive negative integers, and if x > y > z, which of the following must be a positive odd integer?A. xyz B. (x - y) (y - z) C. x - yz D. x(y + z) E. x + y + z ans) let x=-2 ,y=-3, z=-4substitute in the given optionsonly B gives a positive odd integer
64) xy is not= 0col a: -x-ycol b: x+yans) i think ans is D....bcoz take x= -1 n y=-1 then cola :2 colb:-2now Take x=1 n y=1 then cola:2 colb:2
65) a triangle is given and in that taking vertices as centres arcs were drawn with 2 cm as radius so that it symbolizes like angles as we represent in geometry and was told to find the length of the arcs
ans) sum of 3angles =180..ie 1/2 of the full circle.i asked 2 find d lenght of the arc...so its
length of arcs ie circumference when 360 =2*pi*rwhen it is 180 length= ½* 2pi*r=1/2*2*pi*2=2pi
66) at a dress show room a dress was sold with profit at a rate of 20%......what is the % of profit in the cost priceAns) let cost of dress be 10 Sold at a rate of 20% profit=20/100*10=2Cost price of dress=10Q is what is the % of profit in the cost pricewhat is the % of 2 in the 10=20%ans is 20% 67) Mean weight of apples in a basket is 4 ounces, and their standard deviation is 0.8. Col A : The weight of the apple with 1.5 standard deviationCol B : 3.2 ouncesAns) mean weight of apples=4 n SD =0.8Standard deviation depends up on the the deviation of the weight of apples from its mean weightApple with 1.5 SD mean its weight deviated from mean weight i.e 4.this deviation may be +ve deviation or –ve deviationThat means weight of the apple may be >4 or <4so, aquare="2rArea="4r^2Area" region ="4r^2-pi*r^2">0Col A : x+yCol B : 0Ans. D
70) n is the least possible no. such that 18n is a perfect square. m is the least no. such that 9m is a perfect square. Col A : nCol B : mAns.) 18n=18(2)=369m=9(1)=9 m=1 n=2 here n>m
well if n & m not given interger than u`l have to take n = 1/18 and m = 1/9 so m > n...
ans is D.
field problem with r sections and t farms....but u need to change that there are 5 workers and the work is equally divided among them and betty and rachel are 2 of the 5 workers.rest is samecola amount of bettycolbrt/4
ans) amount of betty=rt/2
ans is A
71) One triangle made inside the other (Let me try and xplain the diagram say PQR is inside XYZ such that PQ XY and QR YZ and P when extended meets X and R when extended meets Z) Now external angle at X is x. Internal angle at P is y. and internal angle at Z is z. Col A : xCol B : y+zAns. C they are equal.72) (14^10+7^2)^2-(14^10-7^2)^2Ans) it is in the form of (a+b)^2-(a-b)^2=4abWhere a=14^10 n b=7^2(14^10+7^2)^2-(14^10-7^2)^2=4*14^10*7^22^2*(2^10*7^10)*7^2=>2^12*7^12=>(2*7)^12 =>14^1273) 2, 3, 5, 8, 7 , 9 r all +ve integers ..... if three digits nos r taken using each number only once... then.
col A -. the maximum possible sum of the numbers.colb -> 1459 Ans) max possible no=952+873=1825 976+854Ans is A
74) . col a--------------------------------------- col b(2^7)(5^15)+(2^7)(5^15) --------- (5^7)(10^8)
Ans) cola:2^8*5^15
Colb: (5^7)(2^8*5^8)2^8*5^15Ans is C
75)6-x-x-3 ....find the value if x=-3.ans) 6+3--3-3=9-6=3
76) in one vase there is some tulip &rose. prob of rose is k & that of tulip is 2k.col a=kcol b=1-kans b
77) one di q that was of like if 16 men have to be carried in a 3 boats the same q discussed many times...ans:1>1/4
78) if x,y,z are divisible by 7 and remainder is 3 then wat is the remainder wen x+y+z is divided by 7.ans: let x=7+3,y=14+3,z=21+3 gives reminder 3 when divided by 7X+y+z=51 51/7 gives reminder 2Ans is 2
79) if p is a positive integer then how many values will there 4 p such that 36p is a factor of 720Ans) 1,2,4,5,10,20 36*20=720….indirectly factors of 20 will be the ansTotal 6 values
80) if net income=annual revenue-expenditure and if net income=4*expenditure then wat is expentiure as a fraction of annual revenue.ans:given I=R-E n I=4*E4E=R-E5E=RE=1/5*RAns is 1/5
81) a no was given like H_P0__ 4for the first blank can be a letter from 26 alphabets for the 2nd and 3rd blank is a digit then wat is total combination (different)ans):26*10*9
82) ....If a cmpny R has 50 more employees then S and another company T has 1/4 no of emloyees of R .col a col bno of employees no of employees in a company Tin a company S ans) R=50+ST=R/4Let S=50 then R=100T=100/4=25 S=50 and T=25Ans is A
corrected answerAns is D
83)15 < x <30 x="16" y="34" xy="2<6Case">6
Ans is D
86) a person spends same amount from his salary everymonth.Last year if he spends 6 months of salary . then wht fraction of salary he spends everymonth. Ans) : 1/2.
Aug 11 87) the ratio of circumference of 2 areas is 4:1 find ratio of their areas.options were 2:1 4:1 12:1 8:1 ans) let it be circumferences of circle2*pi*r1=4 n 2*pi*r2=1r1=2/pi n r2=1/(2*pi)ratio of their areas=pi*r1^2:Pi*r2^2=r1^2:r2^2=4/pi^2:1/(4*pi^2)=4:1/4= 16:1
88) two lines are parallel n and p, two line l and m intersect n at a point.such that a triangle is formed between n and m. we need to find if the two sides of the triangle are equal or not. its comparison question. the third side is base of p.Ans ) is D
89) 2.007/.007 + 2.007/7
ans) 2007/7+2.007/7=2009.007/7=287.001
90) R is a multiple of 3 and S is a multiple of 7 what is the least number that divides the product of R and S exactly options were like 21,42 168 dont remember the options exactly ans) 3 is a multiple of 97 is a multiple of 21R*s=9*21=189 is divisible by 21
91)there were 60 chocos divided amond jan, philip and phylu jan got more than philip and got more than phylu also colA colBnumber of chocos jan got 21 or 22 dont remember exactly
ans) jan should have min 21 chocos to be more than Philip n phyluAns is D
92) draw the figure...draw two lines AB n BC so that they form an angle at B.noe draw two lines from point B so that they make an angle 'a'mark the line nearer to A as L and other one nearer to C as 'M . NOW AngleABM='x'=74 degrees(given) n AngleLMB='a' = 20 (given)Angle LMC='y'And Angle ABC=82degrees( given)think u got the diagramfind x-y
so 'y'=(ABC-x)+au will get y=(82-74)+20--------y=28
finally x-y=74-28==========46degrees is the answers
93) x=10y+2cola: tens place digit of xcolb:units place digit of yANS) ans is D ie cant be determined--take x = 22 then y =222 here it seems ans is btake x= 82 then y= 822 here its a.therfore ans: d
94) Two circles A n B.A's diameter is half of B's Diameter.Cola:no.of revolutions A makes in 5000mcolb:NO.of revolutions B takes toin 2500m
Ans) for one revolution A ---covers 2*pi*r distancefor one revolution B ---covers 2*pi*(2r) distance
let X be no of revolutions by A in 5000 metersthen X*2*pi*r = 5000
let Y be no of revolutions by B in 2500 metersthen Y*2*pi*(2r) = 2500
divide both the values
[ X*2*pi*r]/[Y*2*pi*(2r)] = 5000/2500
by implifying we get
X/(2*Y) = 2
X= 4Y
Answer is A.95) g(X)=3power(x-1)
then( g(x+1)-g(x))/2==3^x-3^(x-1))/2
=3^x(1-1/3)/2
=3^x(2/3)/2
=3^(x-1)
96) y<0 2="y^2+5col"> 0 doesn't imply whether x>0 or x<0. 64="9/64Colb:1/216Ans" 55="3025" 3="x" s1="cuberoot(x)S2^3="2x" s2="cuberoot(2x)s1/s2="cuberoot(x/2x)="cuberoot(.5)<.5ans" 15c12=" 455" r="60+ST="R/4Case" s="40" r="100T="100*(3/4)="75" s="40" t="75CASE" s="140R="240T="180Ans" a="455B="300C="60D="15E="12" 15c12="455" a=" no" b =" no" x="47" 2="477^x="root(47)" 3600="3600/3600-900pi/3600="1-pi/4="(4-pi)/4" 7a="2B="4C="6D="8E="10ans)" n="7+3="10n^2-5="10^2-5="9595/7" kg="2.2" class="" z="----" a="2.2" 4z="0." day="(44+46)/2=45" avg="44Last" 33sd="{((11-22)^2+(22-22)^2+(33-22)^2)/3}=root{(11^2+11^2)/3}">> x=y+2ztherefore here x,y,z cant be negative,hence: x > y and x > zans: col A.
113) )a man sold product X for 25% profit and Y for 25% loss..if he sold them for 210000 each then the sum of their original products is how much greater than 420000?1.02.140003.360004.420005.28000
Ans) product x : (25/100)*x+x=210000x/4+x=210000x=168000product y: y- (25/100)*y=210000y=280000x+y=448000original product is 448000-420000=28000 greater than 420000
ans is 28000
114) diameter of a circular region of area 4pie is used as unit of length how many units of lenghts is diameter of a circular region of area 100pie51012 1/22025ans) pi*r^2=4*pir=2 d=4pi*r^2=100*pir=10 d=20
4*5=20 so,5 units length is diameter of a circular region of area 100pi
116) cola (35^1/2-26^1/2)^2 col b (35^1/2-26^1/2)
Ans) root 35 is 5.x and root26 is also 5. y on substraction we get a value <>rFind relationship b/w them
ans) s< r
from equation observe - y>z (for x to be +ve) hence x>y 125) A tree grows for 6 weeks..1st week it grows 1/4..then 1/5.then 1/6...then 1/7..then 1/8...then 1/9....Second tree grows 3/4th in 6 weeks...col a col btotal growth of tree 1 total growth of tree 2
Ans) ans is D
bcoz we dono the heights of both trees....we can't tell which tree grows larger 126)20% of 1/16 25% of 0.05Ans) cola:1/80 colb:1/80
Ans is C
127)1+2*square root of 3 3+square root of 3
Ans) cola:1+2*1.7=4.4Colb:3+1.7=4.7Ans is B
128). 33< x <35 x="34" an="" s5="sum"> S5=5n-10
5n-10+x=6nX=n+10
Ans is A
130) Given a triangle with two angle 60 (which means it is an equilateral triangle ) and two side are given as x+4 and y-3Col A Col Bx yans) y>x for all valuesAns is B 131) In a country the only 13 ppl were currently using cell phones and it is expected that it will increase to 925%in the next 10 yrs .How many ppl will be using cell phones after 10 yrs.(wordings and number may change i dont remember exaclty BUT THE SENSE is the same)
Ans) ans is 133
for 900% inc ppl=13*9=117for 25% inc ppl=3.25for 925% inc ppl=117+3.25+13=133.25=133
132 )GIven a triangle ABC in the coordinate axis. the coordinates of all the three points A,B,C were given and angleB is given as xCol A Col Bx 90
ans) as the coordinates were given u got to find the distance they will be root20,root5 and 5 They follow pythogorous theorm so x=90ANS is c
133) one question was about exponents and bases all u had to know is the basic formulae like x^a * x^b=x^(a+b), (x^a)^b=x^ab and so on I dont remenber the numbers the answer was 14^12
134) ((x-1)^2 )-1 <0col 2="=-240D">a+b then which must be trueI eleminted all the option expect 2a)ab<0b)a+b<0ans) 2="8A" x="2" s="Set" 6t=" Set" a="cuberoot(x)Side" b="cuberoot(2x)Ratio="cuberoot(1/2)">1/2
Ans is A
142) A B(0.001)-1 + (0.9999)-1 (0.002)-1 + (0.9998)-1 Ans) (1.0009-2)<(1.0018-2)Ans is B 142)From the figure below, it was asked that if AD=DC,and the co-ordinates of all the three vertices of the triangle were given.(D is between A and C)A BArea of triangle ADB 10 Ans is C 143) No. of articles sold 15 10 30 45Price per unit( in dollars) 10.15 18.5 14 12 What is the approximate average price per unit? Ans) sol: (15*10.15+10*18.5+30*14+45*12)/(15+10+30+45)=12.97 144) 12 people sitting around a circular table each will require minimum place of 2.75,what is the least dia of table possible Ans) circumference of table=2*pi*r=12*2.75=33R=33/6.28=5.25Diameter =10.5So,least diameter of table possible=11 145) IF A&B are no’s from 200 to 999 andtens place of A is 8 tens place of B is 6column A column B A-B 2 Ans) A=x8y B=a6bX n a need not be equalAns is D 146 )A triangle ABC was inscribed in a semi circle and sides of the triangle were given 6&8 and a line is drawn from vertex of triangle to the center D and asked to find the lenth of line of B to D it becomes radius of triangle 0 6 8 10 12 ANS) :10 147) Area of a circular region given 250 and asked to find the radius of the circular region Ans) pi*r^2=250R=8.9 148) One std dev problem was given the median of 101 numbers is 50 and the std devation is zero.Cola Col BAverage arthematic mean of 101 numbers 50 ans) std deviation becomes 0 only when all the 101 numbers are equal median is given as 50 ...so all 101 numbers are 50 so arithmetic mean=50 ans is C 149) if 3 books are moved from shelf S to shelf T then both S and T will be having the same number of buks....and if 7 buks are moved from T to S then S will be having 3 times ans) s-3=t+33(t-7)=s+7solving this we gots=23t=17 150) col a col b2^-3*4^-3 6^-3 ans) cola: 8^-3=1/8^3colb:6^-3=1/6^3ans is B151) cola colb1/101+1/102+1/103 1/103+1/102+1/101 Ans) both r equal C is the ans 152) avg in 3 tests 86 how much should get in 4th to score avg 89 Ans) S3=sum of first 3 testsS3/3=86 => S3=258Let x be the 4th test score(S3+x)/4=89258+x=89*4X=356-258=9898 is the ans
153) cola colb 4*100^2 .004*100^2Ans) A is the ans
154) cola colb sum of the squares of sum of the squares offirst 100 even numbers first 100 odd numbers
ans) cola: 0^2+2^2+4^2+6^2+…….+198^2colb: 1^2+3^2+5^2+7^2+……..+199^2
if u compare 1st ,2nd ,3rd…..100th term of cola n colb ….colb have high value numbers
ans is B
153) cola colb 4*100^2 .004*100^2Ans) A is the ans
154) cola colb sum of the squares of sum of the squares offirst 100 even numbers first 100 odd numbers
ans) cola: 0^2+2^2+4^2+6^2+…….+198^2colb: 1^2+3^2+5^2+7^2+……..+199^2
if u compare 1st 2nd 3rd…..100th term of cola n colb ….colb have high value numbers
ans is B
155) UTAH & MAINE..there are these to words..if u choose 1 alphabet from,what is the probablity that they are not same..ANS):8/9 there are 8 unique wordstotal no of words=9
156 )There is code that is of the form..
_ _ _ _ _..ie 5 blank spaces..first there 3 blank can take any alphabet(expect the vowels)..repetation allowedand last 2 blank any no from 0-9..repetaion allowed..what r the diff poss values?
ANS):21*21*21*10*10
157) A right angle triangle lies inside a semi-circle such that,the hypt=diameter of the semi-c..remaining two sides are x & y..col A:x*x+y*ycol B:4r*r..
ANS): cola: x*x+y*y=(2*r)^2=4r*rColb: 4r*rAns is C
158) consider triangle ABC..Ang ABC=40..AC is the base..
extend AC on both the sides..such that one angle is X and other Y..(external angles)wat is the value of X+Y..
ANS) X+Y=A+C+40+40A+B+C=180A+40+C=180A+C=140X+Y=140+40+40=220
159)For road widening the length of a rectangular plot is decreased by 15% and its breadth is increased by 15%.ANS Acol A-->area of the original plotcol B-->area of the changed plot
Ans) the length of a rectangular plot is decreased by 15% so length=.85L
its breadth is increased by 15%. So,breath=1.15B
cola: area of original plot=L*B=LB
colb: area of the changed plot=.85L*1.15B=.97LB
ans is A
160) .a vas contg onlyroses and tulips. probability for taking roses is k and that for tulips is 2k.colA colB k 1-kAns) let no roses=xNo of tulips=yProbability for taking roses=k=x/(x+y)
Probability for taking tulips=2k=y/(x+y)
1-k=1-x/(x+y)=(x+y-x)/(x+y)=y/(x+y)=2kB is the ans
161) 2.007/.007+2.007/2 is approximately = ?a)0b)30c)s.td)300 (ans) :D we 'll get approx. 287.7)
162) (4x-2y)(6x+3y)=18cola 4x^2 - y^2 colb6
Ans) 24x^2+12xy-12xy-6y^2=1824x^2-6y^2=186(4x^2-y^2)=184x^2-y^2=3
163) if n is a positive integer thencola no.of +ve factors of 2n
colbno.of +ve factors of n
ans) ans is A
164) a square is given of area 80 is cut 2 sides parallelly.....after cutting only 3/4 is remaing
Ans) 3/4th of 80 =(3/4)*80=60
Remaining area =60
165) a1=5 a2=10 a3=10^5in general an=[a(n-1)]^[a(n-2)]no of digits in a5?
ans) :
Now you know a1=5 a2=10 a3=10^5
And we have an formula i.e an=[a(n-1)]^[a(n-2)]
you need a5........Just substituite n= 5 in question .....
so a5= [a(5-1)]^[a(5-2)]= a4^a3
We dunno a4.......calculate a4.............Just substituite n= 4 in question .....
a4= [a(4-1)]^[a(4-2)]=a3^a2=(10^5)^10=10^50
Subs back again a5= a4^a3a5 =a4^a3 =(10^50)^(10^5) =(10^50)^(100000)=10^(5000000)there fore no of digits 5000001
166) 1,2,3,4,5 r the five numbers givenprob of selecting 2 numbers tht their product is an odd number..
Ans) product of two numbers is odd when both the numbers are odd
Probability=3/5*2/4=3/10
167) Col A Sum of first ten even numbers col Bsum of first ten odd numbers
ans) cola: 0+2+4+6+8+10+12+14+16+18colb: 1+3+5+7+9+11+13+15+17+19
comparing 1st,2nd….10th terms of cola ans colbcolb has greater numbers
ans is B
168) a number when divided by 3 leaves a remainder 1. whent the same number divided by 15 leaves the remainder 13? Options: 15,27,35,43
Ans) by elimination 43 is the ans
43%3=1
43%15=13
169) A(*)B = (A^2 - B^2)\AB
Col A : A(*)B Col B : B(*)A
Ans) col a: (A^2 - B^2)\ABCol b: (B^2 - A^2)\ABwe don’t know the values of A & Bans is D
170) Total Annual income of 600 companies are determined. From this Estimated Annual Incomes(EAI) are determined. F,G,H are three companies which have EAI as 30,40,and 60 percentile of the total.A Difference in EAI between F and G BDifference in EAI between G and H
Ans) let the total be X
EAI of F=(30/100)*XEAI of G=(40/100)*XEAI of H=(60/100)*X
Col a: diff in EAI b/w F and G
(40/100)*X-(30/100)*X
=(10/100)*XCol b:
diff in EAI b/w G and H
(60/100)*X-(40/100)*X
=(20/100)*X
171) Certain no. of people were being checked for a certain disease. It was found that 10% of them were below 20yrs and had that disease. It was also found that all the people who were found to have that disease, 60% of them were 20 or above 20. Find fraction of people who were found to have that disease
Ans) let x are total no of personsley y be persons infectedno of persons infected below 20yrs=0.1xno of persons infected above20 or equal to 20=0.6ytotal no of persons infected=0.1x+0.6y----------------Aalso 0.4y=no of persons infected below 20 yrsso 0.4y=.1x0.6y=0.15x-----B put this in eqn Afraction =[0.1x+0.15x]/x=0.25
172) The perimeter of the rectangle is 20 , a triangle was inscribed in the rect with its base equal to its length and height equal to its width . need to find out area of the rect ? a) 10b) 12c) 24d)20ans) by elimination method only 24 satisfies area n perimeterPerimeter=6+4+6+4=20Area=6*4=24173) 3^n + 4 is divisible by 5 find the value of na) 23b) 24c) 25d) 26e) 27 Ans) by elimination methodIn 3^n+4If n is divisible by 4 then units place of 3^n is 124 is the only option divisible by 4Now 3^24+4 have 5 in its units placeB is the ans
174) P and N are integers P^2 = 5N Col A Col BN 3 ANS) : D
175) -10< x="6" y="-9Then" y="-15Cola" letx="9X+y=" y="10cola"> colbAns is D176) k = y / x and k = 1/x + 1/y ; express k in terms of y a) 1/( y-1)b) 1/(y+1)c) y/(y+2)d) other options I don't rem Ans) x=2 and y=2 satisfies both K expressionsK=2/2=1 k=1/2+1/2=1 By elimination methodOnly 1/(y-1) satisfies1/(2-1)=1Ans is A 177) The equation was like this (5,00,000 * P / 100-P)and if P is 99 and 90 Then what is the diff when P=99 and P= 90 ANS ) 5,00,000(99-90/10)5,00,000*90 = 450,00,000
178) A square was inscribed in a circle and asked to find out area between the the arcOf the circle and the side of the square ?
Ans ) r=radius of circleDiameter=diagonal of square=2r
Side of square=aa^2+a^2=4*r^2a=root2*r
area of square=2*r^2
area of circle=pi*r^2
difference b/w areas= pi*r^2-2*r^2
area between the the arcOf the circle and the side of the square=
¼( pi*r^2-2*r^2)=r^2/4*(3.14-2)=0.285r^2
179) x < 2 ="c)" p =" 2^-2002," q =" 2^1000col" 4p="4/2^2002="4/(2^2000*2^2)="1/2^2000Colb:q^-2="1/q^2="1/2^2000Ans" x="x,">0...which is -ve.. Ans) x =xx=+x or –xy>0x can be -ve
182) cola.((4.01)^3 - (1.97)^3)/(1.98) Colb18
Ans) cola: take approximate values 4.01=41.97=21.98=2((4)^3 - (2)^3)/(2)(64-8)/2=56/2=28Colb:8
Ans is A
183) . col a (root 2 * root 3)=root 6
col b :root 5
ans is A
184) if the ratio of circumference of two circles are 4:1. Then find the ratio of their diameterans:- )(2*pi*r1)/(2*pi*r2)=4/1
r1/r2=4/1
(2*r2)/(2*r2)=d1/d2=(2*4)(2*1)
=4/1
Ans is 4:1.
185) if A1 = 5; A2 = 10; and A3=(10)pow5; and An = (An-1)pow(An-2) where n>2col a:no of digits in the 5th termcol b:5,000,001 Ans) consider col a
Now you know a1=5 a2=10 a3=10^5
And we have an formula i.e an=[a(n-1)]^[a(n-2)]
you need a5........Just substituite n= 5 in question .....
so a5= [a(5-1)]^[a(5-2)]= a4^a3
We dunno a4.......calculate a4.............Just substituite n= 4 in question .....
a4= [a(4-1)]^[a(4-2)]=a3^a2=(10^5)^10=10^50
Subs back again a5= a4^a3a5 =a4^a3 =(10^50)^(10^5) =(10^50)^(100000)=10^(5000000)there fore no of digits 5000001
Ans is C
186) 24%passed in m1. 75%passed in m2. and 23%failed in either. then find the people passed in both.
ans)U=union
^= interswction
People passed in either =
P(A U B)=100-P(A^B)
=100-23 = 77%
People passed in both=
P(A^B) = P(A)+P(B)-P(A U B)
=24 + 75 - 77 = 22%
ANS IS 22%
187) . ((x)^(n+1)/(x)^(n-1))+((x)^(n-1)/(x)^(n+1))
ans) [x^2(n+1) + x^2(n-1)] / x^(2n)
[( x^2n*x^2) + (x^2n*x^-2)]/x^(2n)
X^(2n) *[ x^2+ x^-2 ] / x^(2n)
X^2 + x^-2
X^2 + 1/x^2
188) Col A: The no. of even squares that are less than 100Col B: The no. of odd squares that are less than 100ans) even squares are=0,4,16,36,64odd squares are=1,9,25,49,81
ans is C
189) . (X) pow (2) = (y) pow (2) + 5;Col A: XCol B: Yanswer is D. can't be determined from the information
190). i got the triangle question in triangles.// / / \ 90 \ \ 90_\
and they gave the other angles as x,y,w,z.They asked the relations between them
For this I and II and III all are correct.SO the option is 5.dont brain storm at this question simply put the option 5.
191) A line is passing through (0,10) and (5,0)There is one more line with slope m parllel to this line
Col A: mCol B:-1/2
ans)Given(x1,y1)=(0,10)
(x2,y2)=(5,0)
Slope m of the parallel line is equal to the given line passing through (0,10) and (5,0)
Slope of line through the give points
=(y1-y2)/(x1-x2)
=(10-0)/(0-5)
=-2
Cola: Slope m=-2 Colb: -1/2
Ans is B
192) so ter r two parallel lines vertically...two transversals r drawn.....such tat they meet at one of the parallel lines...and a triangle is formed...col a:one side of the tricolb:another side..
Ans) ans should be D….bcoz accoding to given information
Triangle formed can be any of these
* Righ angle triangle*Isosales triangle*Equilateral triangle *triangle with all sides unequal*isosales right angle triangle
So ans is D
193)x is +ve integer & is a factor of 3x+1Col A-------------------------Col B(-1x)---------------------------1Ans) let x=1
3x+1=4
1 is a factor of 4
Cola: -1x=-1 Colb: 1
Ans is B
194)Col A----------------------------Col BSqrt(24)-1-------------------Sqrt(10)+1 Ans) Cola: sqrt(24)-1
= 4.x-1
=3.x Colb:sqrt(10)+1
=3.x+1
=4.x
Ans is B
195)0 < s
t2/f=60 =>t2=60f
(t1+t2)/(m+f)=58
(54m+60f)/(m+f)=58
54m+60f=58m+58f
4m=2f
f=2m
no of female=2 * no of male
colb is greater
ans is B
201) hexagon was inscribed in circle....and was asked to compare diagonal of hexagon n length of arc...
ans) length of the diagonal of a hexagon = diameter of the circle
length of arc > diameter of circle
202) . 14^n is divisible by 32 where n is integercola: n colb: 4ans) given 14^n is divisible by 32
(2*7)^n is dividible by 32
(2^n)*(7^n) is divisible by 2^5=32
[(2^n)*(7^n)]/(2^5)
By comparing numerator and denominator
7^n cannot be divisible by 2^5
2^n is divisible by 2^5 when n>=5
n minimum value=5
cola is greater
ans is A
203) r1 = 13.2, 14.2,15.2,16.2,17.2,18.2r2 = 13 x .2, 14 x .2 , 15 x .2 , 16 x .2 , 17 x .2 , 18 x .2r3 = 13/.2, 14/.2, 15/.2, 16/.2, 17/.2, 18/.2
was asked to arranges SD in ascending order
ans)
let SD of r1= z
SD of r2 = (SD of r1) * 0.2=z*0.2
SD of r3=(SD of r1)/0.2=z/0.2
r1 = z
r2=z/5
r3=5z
SD’s in ascending order
r2 r1 r3
204) . a number n is divisible by 17 n 13..cola n colb 442
ans)
17*13=221
Minumu value of n divisible by 17 and 13=221
442 is also divisible by 17 ans 13
Ans is D
205). 2*x^3 + A* x^2 + B*x + 5 = 0...this is not the exact equation but it was smthing like this....it was stated that equation has three roots... and if x= -1 and x= 2 are two of dem then find value of A Ans) 2*x^3 + A* x^2 + b*x + 5 = 0
Above equation has 3 roots
2 roots are given x=-1 and x=2
2 roots are enough to find A …..
bcoz there are only 2 unknown variables A & B
substitute x=-1 in the equation
A-B+3=0 ---- 1
substitute x=2 in the equation
4A+2B+21=0 ----- 2
SOLVING EQUATIONS 1 & 2
A= -9/2
206)if x>60 and y>60 what is the approximate value of(x+(1/y))/12x
.ANS)
Let x=60.00001 =60 (approximatelt)
Y=60.00001 =60 (approximatelt)
(x+(1/y))/12x =
(60+(1/60))/(12*60)
=3601/(60*60*12)
=3601/(3600*12)
1/12 (approximately)
207) cola:Nos divi by 3 b\w 1 to 50colb: Nos divi by 3 b\w 51 to 100
ans:)
208) cola: -2^-3 colb: -4^-3
ans) cola:
-2^-3
=1/(-2)^3
= -1/8
colb:
-4^-3
=1/(-4)^3
=-1/64
-1/64 > -1/8
Ans is B
209) ) the quest ws lik..... x>1x*=x\(x-1) which of foll is true.......1. (x*)*=x*2. 1/x*=x*3. (2x*)=2(x)*4. don remm........
Ans) ans is (2x*)=2(x)*
(2x*)=(2*x*)=2(x*)210) In company 1/4 of emp are archit.If 60 emp are added out of which 50 r architthan ratio of archi changes to 1/3.If No emp leaves the job in all there r how many options....180,360,420,720 don remm..................
Ans)
let initial no of employees=x
architects=x/4
60 added to x = x+60
Out of 60 ….50 are architects
Total no of architscts=(x/4)+50
ratio of archi changes to 1/3 =1/3(x+60)
(x/4)+50=1/3(x+60)
By solving x=360
Total no employees=x+60=420
Ans is 420
211) x<1 c =" 10" 10="x" x="1110">79999col a digit in 1000 of x colb6
ans) given x> 79999
case1 :
x=80000 > 79999
1000 digit of x =0 < x="89999">79999
1000 digit of x= 9 > 6
Cola > colb
Ans is D
214) i got the field problem with r sections and t farms....but u need to change that there are 5 workers and the work is equally divided among them and betty and rachel are 2 of the 5 workers.rest is samecola amount of bettycolbrt/4
Ans ) its being asked total betty work so that inc rt/5+work done for rachel=(1/15 + 1/5)rt=4/15*rt=.266 rtwhereas rt/4=.25rtne frm here again A is correct option
215) )Median of 50 numbers is 54. median of another 60 numbers is 56colA:wat is the median of the total 110 numberscol B:55
Ans)
data insufficiant
ans is D
216) If first four letters of a employees batch no are formed by all alphabits except a,e,i,o,u,Y and nest two can be formed by digits 0 to 9 wat is the max employees possibe....if the repetation is considered
Ans) 26-6(a,e,i,o,u,y)=20 0-9=10
Ans is 20*20*20*20*10*10
217) In year 97 salary of A n B are same ...in 98 a sal increased by t percent and b sal inc by m % ...n in 99 A sal inc by m% and B sal by t%....Col A sal of A in 99 col B sal of B in 99
Ans ) Let initial salary=100
t=10%m=20%
yr 98
salary of A=100*110/100=110
salary of B=100*120/100=120
yr 99
salary of A=110*120/100=132
salary of B=120*110/100=132
ans is C
218) The no of ways in which 6 things can be divided into two diff groups containing 3 things and 3 things.......
Ans)
6!/(2!*3!*3!)
=10
219 ) x/7reminder 3find remainder of (2x-1)/7ans)
let x=10
(2x-1)/7
=19/7
Reminder=5
220)x/5remainder 3colA colB(x^2-7)/5 4
Ans) Let x=8
Cola:
(x^2-7)/ 5
(64-7)/5
57/5
Reminder= 2
For any value of x reminder=2
Colb: 4
Ans is B
221.1/4^n < n="5" 5="1024">=5
ans is D
222) .G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X..then how much time it takes to so that the tank capacity becomes G/2 gallons of water.
Ans)
G is the capacity of water in containernow x
ans) is D
224) .the perimeter of a right isoceles triangle is 1+root2.what is the are of the triangle.ans)
Perimeter=
x+x+xroot2=1+root2
x=(1+root2)/(2+root2)
x= 1/root2
area=1/2*x*x
½*1/root2*1/root2
=1/4
Perimeter=
x+x+xroot2=1+root2
x=(1+root2)/(2+root2)
x= 1/root2
area=1/2*x*x
½*1/root2*1/root2
=1/4
225) z>y>x>1colA colBz(x+y+1) y(x+z+1)ans)
For all x,y,z values
Cola > colb
Ans is A
For all x,y,z values
Cola > colb
Ans is A
226) if p is a positive integer then how many values will there 4 p such that 36p is a factor of 720(don't knw the no exactly).
ans ) cola values of pcolb8
for p=1,2,4,5,10,20
36,72,144,180,360,720 are the factors of 720
Total values of p=6 <>
254) Ann buys w kgs of fodder per week to feed her sheep. each sheep eats x kgs/day.col a-No. of sheep Ann hascol b-7w/x
for p=1,2,4,5,10,20
36,72,144,180,360,720 are the factors of 720
Total values of p=6 <>
227) Given a triangle with two angle 60 (which means it is an equilateral triangle ) and two side are given as x+4 and y-3Col A Col Bx y
ans)
it is an equilateral triangle
sides are equal
x+4=y-3
y=x+4
y is greater
ans)
it is an equilateral triangle
sides are equal
x+4=y-3
y=x+4
y is greater
228) there is a 4*4*4 cube ..it is painted on all its 6 faces .. then it is cut in 1*1*1 cubes .. nopw randomly a face is pick frm any cube .. probability that face is colored one ..?
ans)
total no cubes of side=1
=64
No of cubes which are painted
=56
probability that face is colored one
=56/64
=7/8
ans 1/4
total no cubes of side=1
=64
No of cubes which are painted
=56
probability that face is colored one
=56/64
=7/8
ans 1/4
229) )if n/12 rem is 5..wat is val when n*n/8..
ANS)
Let n=17
17/12 rem =5
17*17/8 rem =1
Ans is 1
Let n=17
17/12 rem =5
17*17/8 rem =1
Ans is 1
230)one more Quest on this is abt. meadian ..something like if no.of dependents increased by 2 .....what will be the mediana) 1 lessb) 2 lessc)No changed)1 moree) 2 more (I more
Ans)
Median of a certain series will not be changed by increasing dependents by same value
Ans is C no change
Ans)
Median of a certain series will not be changed by increasing dependents by same value
Ans is C no change
231) Fresh fruit contains 72% water and dry fruit contains 20% water. How much dry fruit from 100 pounds of fresh fruit can be obtained
ans) 38 gm dry fruit A fresh fruit contains 72% of water è 28% of solid In a 100 pounds fresh fruit we will get 28 pounds solid. & also given A dry fruit contains 20% of water è 80 % of solidè with 28 pounds solid we can create 100 pounds dry fruitThen with 80 pound solid, how many dry fruiti.e. (80/100) x 28 = 35 kg......
ans) 38 gm dry fruit A fresh fruit contains 72% of water è 28% of solid In a 100 pounds fresh fruit we will get 28 pounds solid. & also given A dry fruit contains 20% of water è 80 % of solidè with 28 pounds solid we can create 100 pounds dry fruitThen with 80 pound solid, how many dry fruiti.e. (80/100) x 28 = 35 kg......
232) .if a cylinder is empty and it takes 4 hours to fill it and after 2 and a half hours 150 cubic feet was filled, what is the capacity of the tank.
Ans)
5/2 hr----150 cubic feet1 hr----------x?
X=150/(5/2)
=60 cubic feet in 1 hr
Capacity of the tank=60*4=250 cubic feet
Ans)
5/2 hr----150 cubic feet1 hr----------x?
X=150/(5/2)
=60 cubic feet in 1 hr
Capacity of the tank=60*4=250 cubic feet
233) .which has the greatest prime factor 66 or1000.
ans)
prime factors of 66
=2,3,11
Prime factors of 1000
= 2,5
66 has greatest prime factor
ans)
prime factors of 66
=2,3,11
Prime factors of 1000
= 2,5
66 has greatest prime factor
234) 2x^2-2x=0.Xnot equal to 2
col a x col b2 ans) 2x^2-2x=0
x^2-x=0
x(x-1)=0
(x-0)(x-1)=0
X=0 or x=1
Col b is greater
Ans is B
col a x col b2 ans) 2x^2-2x=0
x^2-x=0
x(x-1)=0
(x-0)(x-1)=0
X=0 or x=1
Col b is greater
Ans is B
235) (x-2)^(x-4)=4 cola x, colb 4
ans)
for any value of x given xpression is no satisfied
ans is D
236) A’s salary is 2000greater than B’s .if A’s salary is increased by 10% and B’s salary increased by 15%col a salary of A after incr colbsalary of B after incr
ans)
let x be salary of A
salary of A after 10% inc
1.1x+2200
salary of B after 15% inc
1.15x
Case1:
if x=10,000
cola > colb
case 2:
If x=1,00,000
Cola <>
Ans)
X=3/8 of ribbon
Remaining= 5/8
Y= 2/5*5/8 = ¼ of ribbon
Total ribbon used=3/8+1/4=5/8
Remaining= 3/8 th of ribbon=45
Length of ribbon=45+75=120 <>
252) A walks with a speed of 65mil/hr to some place and returns with a spped of 35mil/hr. Find the difference in speed in KM/HR(I km=0.621 miles)
253) A group of boy go to play a game. The boys arriange themselves into 8 groups containing 6 boys per group and two are left. After some time, the boys re arrarrage the selves into groups containing equal number of memebers and one is left. What is the number of boys in each group.
ans)
for any value of x given xpression is no satisfied
ans is D
236) A’s salary is 2000greater than B’s .if A’s salary is increased by 10% and B’s salary increased by 15%col a salary of A after incr colbsalary of B after incr
ans)
let x be salary of A
salary of A after 10% inc
1.1x+2200
salary of B after 15% inc
1.15x
Case1:
if x=10,000
cola > colb
case 2:
If x=1,00,000
Cola <>
237) if n divided by 7remainder is 3 wht is remainder when (n+n+n)/7
ans)
Let n=10
10/7 rem =3
(n+n+n)/7
=(10+10+10)/7
=30/7 rem=2
ans)
Let n=10
10/7 rem =3
(n+n+n)/7
=(10+10+10)/7
=30/7 rem=2
238) x^2 - 2x=0 and x is not equal to 2colm a colm b2x^2 0
ans )
x^2 - 2x=0
(x-0)(x-2)=0
Given x not = 2
X=0
Cola = colbAns is C
ans )
x^2 - 2x=0
(x-0)(x-2)=0
Given x not = 2
X=0
Cola = colbAns is C
239)1/x = y/1where x and y are positive integerscolm a colmbx y
Ans) If x =1 and y =1 only above condition is satisfied
Cola=colb
Ans is C
it was abt percent of people who have moved form their state.do remember frds dont waste time in this i hv almost spend 6 mins in this one, ans is people betn age of 60-69.
8 was depend upon same graph.they have asked me about the ratio of people who didnt moved to the people who has moved for age betn age 30-39ans was 83%
Ans) If x =1 and y =1 only above condition is satisfied
Cola=colb
Ans is C
it was abt percent of people who have moved form their state.do remember frds dont waste time in this i hv almost spend 6 mins in this one, ans is people betn age of 60-69.
8 was depend upon same graph.they have asked me about the ratio of people who didnt moved to the people who has moved for age betn age 30-39ans was 83%
240) COL A COLB5/8 ROOT5/8
Ans)
colb > cola
ans is B
Ans)
colb > cola
ans is B
241) x+9=X+5, wat is the value of X
Ans)
X+9=x+5 (this is not possible)
Or
X+9=-(x+5)
2x=-14
X=-7
Ans)
X+9=x+5 (this is not possible)
Or
X+9=-(x+5)
2x=-14
X=-7
242) .two lines l1 and l2 are parallel... points (1,1) and (3,2) are on the line l1. what is slope of l2.
Ans: )
Given lines are parallel…so slopes will be equal
Slope of l1=slpoe of l2
=(2-1)/(3-1)
=1/2
Ans: )
Given lines are parallel…so slopes will be equal
Slope of l1=slpoe of l2
=(2-1)/(3-1)
=1/2
243). x*=x/(x-1)x not equal to 11. (x*)*=x2. 1/x*=x*3. (2x*)=2(x)*4. don remm........
Ans)
(X*)*
= [x/(x-1)]*
= [x/(x-1)]/[ (x/(x-1))-1]
=x
Option 1 is the ans
Ans)
(X*)*
= [x/(x-1)]*
= [x/(x-1)]/[ (x/(x-1))-1]
=x
Option 1 is the ans
244) .A triangle is given.. AB=8,BC=6, Ac=y and Angle ABC=x and x<90.cola==> ycolb==>10
Ans)
If x=90 then y=10
If x<90>
251) X took 3/8 of a roll of ribbon. Of the remining Y took 2/5 of the ribbon. At this point 45in was remining on the roll.col A-the length on the rollcol B-150
If x=90 then y=10
If x<90>
Ans is B
245) . x+2y <-6cola==> x+2ycolb==> 5
ans)
given x+2y <-6 value of x+2y is –ve mod of a –ve value is always +ve x+2y>6
given x+2y <-6 value of x+2y is –ve mod of a –ve value is always +ve x+2y>6
Ans is A
246) (1.1)^2/(0.9)^2 + (0.9)^2/(1.1)^2cola colbvalue 2
Ans)
(1.1)^2/(0.9)^2 + (0.9)^2/(1.1)^2
=(121)/(81)+(81)/(121)
= approx (3/2+2/3) > 2
(1.1)^2/(0.9)^2 + (0.9)^2/(1.1)^2
=(121)/(81)+(81)/(121)
= approx (3/2+2/3) > 2
Ans is A
247) Area of a equilateral triangle inscribed in a circle of radius R.
Ans)
Formula - Side of eqilateral triangle s =root3R
Area of equilateral triangle =(root3/4)*s^2
= (root3/4)*(root3R)^2
=(3root3/4)R^2
Formula - Side of eqilateral triangle s =root3R
Area of equilateral triangle =(root3/4)*s^2
= (root3/4)*(root3R)^2
=(3root3/4)R^2
248)the ratio of males to females is 1:x (x>0)total no of employees 253no of females in terms of xsome options were253x/(x+1)253/(x-1)253(x+1)Ans)
No of females in terms of x
=253*x/(1+x)
=253x/(x+1)
249) some other ques were1,2,3,4,5pick any 2nos probability that product willl b even
No of females in terms of x
=253*x/(1+x)
=253x/(x+1)
249) some other ques were1,2,3,4,5pick any 2nos probability that product willl b even
Ans)
Probability that product will be evev=1- (Probability that product will be odd)
1-3/10
=7/10
Probability that product will be evev=1- (Probability that product will be odd)
1-3/10
=7/10
250) 2^-1, 3^-1 and 4^-1x is any one of the abovey is sum of the other 2col axcol by
Ans)
Case 1: 1/2<(1/3+1/4) Case 2: 1/3 <(1/2+1/4) case 3: 1/4 <(1/2+1/3)
Case 1: 1/2<(1/3+1/4) Case 2: 1/3 <(1/2+1/4) case 3: 1/4 <(1/2+1/3)
Ans is B
251) X took 3/8 of a roll of ribbon. Of the remining Y took 2/5 of the ribbon. At this point 45in was remining on the roll.col A-the length on the rollcol B-150
Ans)
X=3/8 of ribbon
Remaining= 5/8
Y= 2/5*5/8 = ¼ of ribbon
Total ribbon used=3/8+1/4=5/8
Remaining= 3/8 th of ribbon=45
Length of ribbon=45+75=120 <>
Ans is B
252) A walks with a speed of 65mil/hr to some place and returns with a spped of 35mil/hr. Find the difference in speed in KM/HR(I km=0.621 miles)
Ans)
Diff in speeds= (65-35)/0.621
=30/0.621
=48.3 Km/hr
Diff in speeds= (65-35)/0.621
=30/0.621
=48.3 Km/hr
253) A group of boy go to play a game. The boys arriange themselves into 8 groups containing 6 boys per group and two are left. After some time, the boys re arrarrage the selves into groups containing equal number of memebers and one is left. What is the number of boys in each group.
Ans-c)
Initially 8(groups)*6(boys per group)+2(left)=50
After rearrangement
7(groups)*7(boys per group)+1(left)=50
No of boys in each group=7
Initially 8(groups)*6(boys per group)+2(left)=50
After rearrangement
7(groups)*7(boys per group)+1(left)=50
No of boys in each group=7
254) Ann buys w kgs of fodder per week to feed her sheep. each sheep eats x kgs/day.col a-No. of sheep Ann hascol b-7w/x
Ans)
W kgs per week
w/7 kgs per day
given each sheep eats x kgs/day
no of sheeps Ann has =
(w/7)/x
w/(7x)
colb is greater
ans is B
255) A line l passes through points (n, n+1) and (1,1) and lime m passes through (n, n+1) and point (2,2). and n>0col a-slope of lcol b-slope of m
Ans)
Case 1:
Let n=1
Slope of l > slope of m
Case 2:
Let n=2
Slope of l <>
256) n>5col a: 1/n+1/(n-1)col b: (1/n)^2+(1/(n+1))^2
257) x and y are two numbers such that x^2y^2=22. what can be the sum of x and y
Ans-)
Root22 + 1
Or
Root11 + root2
Depends on the options given
Aug 22(5 days ago) 258) A professor gives A, B, C, D and E to a class of students. What is the minimum number of students so that atleast 6 students get the same grade.a)24 b)25 c)26 d)
259) a bag x contains 6 fruits- 3 apples 3 pearsa bay y contains 8 fruits- 4 apples 4 pears wat is the prob tat 2 apples ra taken out simultaneously
260) A(3,0) B(3,4)p is a point that is equidistant to the points a and b
ans)
There are infinity points which are equidistant from A and B
Ans is D
261) IN A PARALLELOGRAM 6X,120 ARE THE OPPOSITE ANGLESAND OTHER IS 3Y FINDCOLA:XCOLB:Y
Case 1:
Let n=1
Slope of l > slope of m
Case 2:
Let n=2
Slope of l <>
ans is D
256) n>5col a: 1/n+1/(n-1)col b: (1/n)^2+(1/(n+1))^2
Ans) is A
257) x and y are two numbers such that x^2y^2=22. what can be the sum of x and y
Ans-)
Root22 + 1
Or
Root11 + root2
Depends on the options given
Aug 22(5 days ago) 258) A professor gives A, B, C, D and E to a class of students. What is the minimum number of students so that atleast 6 students get the same grade.a)24 b)25 c)26 d)
27Ans-c)
A--- 1, B---2, C---3 ,D---4, E---5
again... A---6, B---7.. & SO ON
so after 5 rounds, i.e. 25 students, 5 students will have 5 same grades....
so the next one will be the first one to get 6 same grades
A--- 1, B---2, C---3 ,D---4, E---5
again... A---6, B---7.. & SO ON
so after 5 rounds, i.e. 25 students, 5 students will have 5 same grades....
so the next one will be the first one to get 6 same grades
so the ans is 26
259) a bag x contains 6 fruits- 3 apples 3 pearsa bay y contains 8 fruits- 4 apples 4 pears wat is the prob tat 2 apples ra taken out simultaneously
Ans)
Prob of taking 2 apples from bag x
= 3/6*2/5=1/5
Prob of taking 2 apples from bag y
= 4/8*3/7=3/14
Prob of taking 1st apple from bag x and 2nd apple from bag y
=3/6*4/8=1/4
Total probability
=1/5+3/14+1/2=26/35
Prob of taking 2 apples from bag x
= 3/6*2/5=1/5
Prob of taking 2 apples from bag y
= 4/8*3/7=3/14
Prob of taking 1st apple from bag x and 2nd apple from bag y
=3/6*4/8=1/4
Total probability
=1/5+3/14+1/2=26/35
260) A(3,0) B(3,4)p is a point that is equidistant to the points a and b
ans)
There are infinity points which are equidistant from A and B
Ans is D
261) IN A PARALLELOGRAM 6X,120 ARE THE OPPOSITE ANGLESAND OTHER IS 3Y FINDCOLA:XCOLB:Y
ANS)
6x=120
X=20
Sum of other two opposite angles=360-(120+120)=120
3y=60
Y=20
X=y
Ans is C
6x=120
X=20
Sum of other two opposite angles=360-(120+120)=120
3y=60
Y=20
X=y
Ans is C
262))this is my first questin regarding co-ordinate geometry. three points were given (2,2),(3,6),and (6,5) and asked to find whether angle x
col a x col b 90
col a x col b 90
Ans B
Draw the tri on co-or axis,you calculate the distances between sides,
these are DI questions......
1)got DI on probabality that was very easy you just need to know basics of probabilityit had two questions they were single bar graphs with very easy to calculate numbers
2)another DI was on percentage given in pie graphs was bit tough but can manage if you are thorough wid percentage . it had two questions
3) .32(597)/ .987 asked to find the appromate value iam not sure of values but it was of this model options werelike 20 ,60 etc
4) I cant remember full question there is dinner hall one should be selecting from each of these there are 5 spoons, 4plates, 3dishes how many ways can select.
My graph question was some thing like this It is a column graph. The white column indicates the No. of people moving either out of the city or out of the state.And the black one indicates the no. of people moving out of the state. I don’t remember the exact values but I know all the exact answers
5)Ratio of the No. of people moving out of the city but not out of the state to the no of people moving out of the state is the highest for which group,
Ans. 60 to 69
6)The no of people under 10 and in 10 to 19 is what percent of the total
Ans. 33% Another graph showed the marks obtaines by 11 students in two test. Test 1 on the x axis and test 2 on the y axis
7)What is the median mark of the class
Ans.120
8)In any test no. of the students which get marks below 40 are what percent of the total.Ans. From the graph it will be L M and N in test 1 and L and P in test 2 are those who get marks below 40 i.e. a total of 4 students (and not 5,because L is repeated). Therefore 4 is what % of 11…..and that’s the ans.
9)some Di was given on a graph of no.of couples and no.of dependents (bargraph). answer of one Question on this is 10% (approx.) (in the option)one more Quest on this is abt. median ..something like if no.of dependents increased by 2 .....what will be the median
a) 1 lessb) 2 lessc)No changed)1 moree) 2 more
(ans:C)
10)One more Di on Doodles......One Quest. answer on this is $58,000.
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